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求解 (2x-2)²-x²=0 9t²-(t-1)²=0
人气:264 ℃ 时间:2020-05-08 09:12:52
解答
①(2 x - 2)² - x ² = 0
(2 x - 2 + x)(2 x - 2 - x)= 0
(3 x - 2)(x - 2)= 0
3 x - 2 = 0 或 x - 2 = 0
x1 = 2 / 3 x2 = 2
② 9 t ² - (t - 1)² = 0
(3 t +(t - 1))(3 t - (t - 1))= 0
(4 t - 1)(2 t + 1)= 0
4 t - 1 = 0 或 2 t + 1 = 0
t1 = 1 / 4 x2 = - 1 / 2
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