> 数学 >
用适当解方程(1)2√x²-√2=0(2)(2x-3)²-2x+3=0(3)(3y-1)²-8(3y-1)+15=0
人气:473 ℃ 时间:2020-05-22 14:40:40
解答
(1)2√x²-√2=0
2|x|=√2
|x|=√2/2
x=±√2/2
(2)(2x-3)²-2x+3=0
(2x-3)^2-(2x-3)+1/4=1/4
(2x-3-1/2)^2=1/4
2x-3.5=土1/2
x1=2 x2=-1.5
(3)(3y-1)²-8(3y-1)+15=0
(3y-1+4)^2=1
3y+3=土1
y1=-2/3 y2=-4/3
推荐
猜你喜欢
© 2025 79432.Com All Rights Reserved.
电脑版|手机版