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数学
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已知a+b+C=0证明a3+ b3+ c3= 3abc
人气:275 ℃ 时间:2020-03-20 07:56:57
解答
a+b+c=0=>a+b=-c
a^3+b^3+c^3=(a+b)(a^2+b^2-ab)-(a+b)^3
=(a+b)*[a^2+b^2-ab-(a+b)^2]
=(-c)*[-3ab]
=3abc
证明完毕
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