已知(a+2)^2+a+b+5的绝对值=0,a+2=0;a=-2;a+b+5=0;b=-5-a=-3;求3a^2-【2a^2b-(2ab-a^2b)-4a^2]-ab的值.=3a²-2a²b+2ab-a²b+4a²-ab=7a²-3a²b+ab=7×(-2)²-3×(-2)²×(-3)+(-2...