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化简sin^2α+sin^2β-sin^2cos^2β-cos^2αsin^2β
人气:379 ℃ 时间:2019-11-07 07:40:17
解答
sin^2α+sin^2β-sin^2αcos^2β-cos^2αsin^2β
=sin^2α(1-cos^2β)+sin^β(1-cos^2α)
=sin^2αsin^2β+sin^2βsin^2α
=2sin^2αsin^2β
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