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已知cos(π/2+α )=2sin(α -π/2) 求sin^3(π-α )+cos(α -π)/5cos(5π/2-α )+3sin(7π/2-α )
人气:169 ℃ 时间:2020-01-31 15:49:18
解答
cos(π/2+α )=2sin(α -π/2)即-sina=-2cosatana=2sin^3(π-α )+cos(α -π)/5cos(5π/2-α )+3sin(7π/2-α )=(sin^3a-cosa)/(5sina-3cosa) (上下同除cosa)=(sin^2a*tana-1)/(5tana-3)=(2sin^2a-1)/7=1/7*(s...
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