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化简根号下(1-2sin10°cos10°)/[cos10°-根号下(1-sin^2 80°)]
人气:124 ℃ 时间:2019-08-19 15:11:41
解答
根号下(1-2sin10°cos10°)/[cos10°-根号下(1-sin^2 80°)]
=根号下(sin10°-cos10°)^2/[cos10°-根号下(cos^2 80°)]
=|sin10°-cos10°|/[cos10°-cos80°] cos10°>sin10°cos80°=sin10°
=(cos10°-sin10°)/(cos10°-sin10°)
=1
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