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数学
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已知X/3=Y/4=Z/6,求(XY+YZ+XZ)/(X^2+Y^2+Z^2)的值
人气:495 ℃ 时间:2020-01-09 05:32:08
解答
x=3y/4,z=3y/2
原式=(3y²/4+3y²/2+9y²/8)/(9y²/16+y²+9y²/4)
=(3/4+3/2+9/8)/(9/16+1+9/4)
=(27/8)/(61/16)
=54/61
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