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x+3y+7z=0 2x+5y+11z=0,求(x^2+y^2+z^2)/(xy+2yz+3xz)
人气:447 ℃ 时间:2020-09-29 05:13:44
解答
x+3y+7z=0 2x+5y+11z=0
x=2z,y=-3z
z=0,x=y=0分式无意义
(x^2+y^2+z^2)/(xy+2yz+3xz),z≠0
=[(2z)^2+(-3z)^2+z^2]/[(-2z*3z-2*3z*z+3*2z*z)
=(14z^2)/(-6z^2)
=-7/3
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