(A + B + C)(B + CA)= 3BC
[(B + C)+ A] [(B + C)-α] = 3BC
(B + C)^ 2 - 一个^ 2 = 3BC
B ^ 2 +2 BC + C ^ 2-A ^ 2 = 3BC
B ^ 2-BC + C ^ 2 = A ^ 2
是有规律的余弦^ 2 = B ^ 2 + C ^ 2-2bccosB
B ^ 2-BC + C ^ 2 = B ^ 2 + C ^ 2-2bccosB
BC = 2bccosB
COSB = 1/2
B = 60度
= 2sinBcosC
=√3cosC
= - √3cos(A + B)
= - √3cos(A +60)
= - √3(cosAcos60-sinAsin60)
= - √3(cosA/2-√3sinA / 2)
= - √3cosA / 2新浪+3 / 2
新浪=√3cosA
A = 60°
C = 180-60-60 = 60度
等边三角形