二元一次方程组(1/2 )x-(3/2)y=-1 2x+y=3怎样解
人气:439 ℃ 时间:2020-06-17 06:46:44
解答
(1/2 )x-(3/2)y=-1 1式
2x+y=3 2式
1式化简得到:
x-3y=-2 3式
2式*3+3式得到:
6x+3y+x-3y=9-2
7x=7
x=1 代入3式得到:
1-3y=-2
3y=3
y=1
解得:x=1 y=1
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