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S(1+lnx)xlnx dx 紧急!
人气:245 ℃ 时间:2020-08-28 23:47:52
解答
∫(1+lnx)xlnx dx
=∫[xlnx+x(lnx )^2]dx
=∫xlnxdx+∫x(lnx )^2dx
=1/2∫lnxdx^2+1/2∫(lnx )^2dx ^2
=1/2x^2lnx-1/2∫xdx+1/2x^2(lnx)^2-∫xlnx dx
=1/2x^2(lnx)^2+C
∫(1+lnx)xlnx dx
=∫[xlnx+x(lnx )^2]dx
=∫xlnxdx+∫x(lnx )^2dx
=∫xlnx dx +1/2∫(lnx )^2dx ^2
=∫xlnx dx +1/2x^2(lnx)^2-∫xlnx dx
=1/2x^2(lnx)^2+C
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