s=1/2at^2得t1=根号2s/a通过第二段位移所用时间：t2=根号2*2s/a-根号2s/a=根号2s/a(根号2-1)同理：t3=根号3*2s/a-根号2*2a/a=根号2s/a(根号3-根号2.所以t1:t2:t3:...=1:((根号2)-1):((根号3)-(根号2)):.((根号N)-(根...