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tan(X+45度)=1/3,(sinX-cosX)^2/cos2x?
A.3
B.-3
C.2
D.-2
人气:207 ℃ 时间:2020-06-02 00:37:56
解答
(sinx-cosx)^2/cos2x
=(sinx-cosx)/(cos^2x-sin^2x)
=(sinx-cosx)/(sinx+cosx)
=(tanx-1)/(1+tanx)
=tan(x-45°)=1/3
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