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化简:sin40度(根号3-tan10度)=?
人气:313 ℃ 时间:2020-09-14 08:07:40
解答
sin40(sin60/Cos60-sin10/cos10 )
=Sin40/(Cos10Cos60) (Cos10Sin60-Sin 10 Cos60 )
=Sin40 Sin 50/ (Cos10 Cos60)
=Sin40 Cos40 / (Sin80 Cos 60)
= Sin80/ 2 /(Sin80 Cos 60)
= 1/(2Cos60)
=1
原式=sin40°(tan60°-tan10°)
=sin40°(sin(60°-10°)/(cos10°cos60°))
=2sin40°sin50°/cos10°
=2sin40°cos40°/sin80°
=sin80°/sin80°
=1
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