f(x)=sin(2x+π/6)+sin²x=sin2xcosπ/6+cos2xsinπ/6+(1-cos2x)/2=(√3/2)sin2x+(1/2)cos2x+1/2-(1/2)cos2x=(√3/2)sin2x+1/2,(1)f(x)的最小正周期为π,由π/2+2kπ≤2x≤3π/2+2kπ,得π/4+kπ≤x≤3π/4+kπ(...