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sin2x·cos3x怎么等于二分之一倍的(sin5x-sinx)的
人气:436 ℃ 时间:2020-05-27 08:54:01
解答
sin5x=sin(3x+2x)=sin2x·cos3x+cos2x·sin3x .(1)
sinx=sin(3x-2x)=sin2x·cos3x-cos2x·sin3x .(2)
(1)-(2)得:
sin5x-sinx=2·cos2x·sin3x
cos2x·sin3x=1/2(sin5x-sinx)
(1)+(2)得:
sin5x+sinx=2·sin2x·cos3x
sin2x·cos3x=1/2(sin5x+sinx)
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