命题p为真,即有:x1和x2是方程x^2-mx-2=0的两个根x1+x2=mx1x2=2|x1-x2|=√(x1-x2)²=√[(x+x2)²-4x1x2]=√(m²+8)不等式a²-5a-3>=|x1-x2|对任意实数m属于【-1,1】恒成立√(m²+8)=3a²-5a-...