左边项根据 cos2x=1-2sin²x 来化,右边项展开
f(x)=2sin²(x+π\4)-cos(2x+π\6)
=1- cos2(x+π/4) + cos2x*√3/2 -sin2x*1/2
=1-cos(2x+π/2) + cos2x*√3/2 -sin2x*1/2
cos那项根据 cos(x+π/2)= -sinx 来化
=1+sin2x +cos2x*√3/2 -sin2x*1/2
=1/2sin2x + √3/2cos2x +1
=sin(2x+π/3) +1谢谢 O(∩_∩)O~