a2+b2+c2-ab-3b-2c+4=0
（a-b/2)^2+3b^2/4-3b+(c-1)^2+3=0
(a-b/2)^2+(c-1)^2+3/4(b-2)^2=0
a=b/2,c=1,b=2,a=1
(a-3c)^b
=(1-3)^2
=2^2
=4你好，再请教，请把这一步（a-b/2)^2+3b^2/4-3b+(c-1)^2+3=0怎么得来的，详细写一下，谢谢a2+b2+c2-ab-3b-2c+4=0a2-ab+b2-3b+c2-2c+4=0（a-b/2)^2-b^2/4+b^2-3b+(c-1)^2-1+4=0（a-b/2)^2+3b^2/4-3b+(c-1)^2+3=0（a-b/2)^2+3/4(b^2-4b+4)+(c-1)^2=0(a-b/2)^2+(c-1)^2+3/4(b-2)^2=0谢谢，我会做了采纳啊，兄弟！！！！！！