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若方程x²+y²-2x+2my+2m²-6m+9=0表示圆,则m范围是?当半径最大时,圆的方程为?
人气:255 ℃ 时间:2019-10-29 13:31:48
解答
x²+y²-2x+2my+2m²-6m+9=0
x²-2x+1+y²+2my+m²+m²-6m+9-1=0
(x-1)²+(y+m)²+m²-6m+8=0
(x-1)²+(y+m)²=-(m²-6m+8)
(x-1)²+(y+m)²=-(m²-6m+9)+1
(x-1)²+(y+m)²=1-(m-3)²
1-(m-3)²>=0
(m-3)²-1
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