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已知tanθ/2 求 1-cosθ除以sinθ
人气:336 ℃ 时间:2020-05-09 04:14:13
解答
两倍角公式:
cosθ=1-2sin²(θ/2)
sinθ=2sin(θ/2)cos(θ/2)
(1-cosθ)/sinθ
=2sin²(θ/2)/[2sin(θ/2)cos(θ/2)]
=sin(θ/2)/cos(θ/2)
=tan(θ/2)
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