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各项都是正数的等比数列 {an}中,3a1,1/2a3,2a2成等差数列(a10+a12+a15+a19+a20+a23)/(a8+a10+a13+a17+a18+a21)
人气:110 ℃ 时间:2020-06-26 23:34:48
解答
给点时间,好吗?设,等比数列公比为q,据题意2×1/2a3=a2q=3a2/q+2a2,得出q=3/q+2,解得q=3(符合题意)
(a10+a12+a15+a19+a20+a23)/(a8+a10+a13+a17+a18+a21)
=a10(1+q^2+q^5+q^9+q^10+q^13)/a8(1+q^2+q^5+q^9+q^10+q^13)
=a10/a8
=q^2
=9
good luck to you,best wishes to your study谢啦!那个q我纠结好久=v=
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