>
数学
>
解不等式:x2+1分之2x+1大于0 x2+2分之2x+1大于1
人气:141 ℃ 时间:2020-09-05 08:39:37
解答
(2x+1)/(x^2+1)>0,
x^2+1>0,上式变为2x+1>0,
2x>-1,
∴x>-1/2.
(2x+1)/(x^2+2)>1,
x^2+2>0,两边都乘以x^2+2,得
2x+1>x^2+2,
∴x^2-2x+1
推荐
不等式3 2x-x2大于等于0的解集为?
.解不等式组 x2-2x-3的绝对值大于x2-2x-3;x2+x的绝对值-2小于0
解不等式: (1)x2+2x-3≤0; (2)x-x2+6<0.
解不等式(x2-2x-35)/(x-2)大于或等于0 急,
不等式x2-2x-3大于0的解集和不等式-x2 5x-6小于0的解集为多少?
据英文解释写出下列单词,首字母已给出.
说明文的说明方法解释?
f(x)=2sin²x-λcosx+5
猜你喜欢
Vanity keeps persons in favour with themselves who are out of favour with all others.
Off track with happiness,with the dye that lonely
0.19+4.39+2.81用简便方法计算
低面周长是1.6m高0.7m圆柱的侧面积
证明a^2+b^2>2a-2b-3
七下数学作业本(2)总复习
donot,well,look,you,very (.)
李商隐《夜雨寄北》的解释
© 2024 79432.Com All Rights Reserved.
电脑版
|
手机版