因为：(x-2)^2+|y+1|=0,所以：x-2=0且y+1=0,所以：x=2,y=-1
所以：5xy^2-{2x^2y-[3x^2y-(4xy^2-2x^2y)]}
=5xy^2-2x^2y+3x^2y-4xy^2+2x^2y=3x^2y+xy^2=3*4*(-1)+2*1=-10