∵33^x=2013,61^y=2013两式两边分别取以2013为底的对数∴log(2013)(33^x)=1log(2013)(61^y)=1∴x*log(2013)33=1y*log(2013)61=1∴1/x=log(2013)331/y=log(2013)61相加：1/x+1/y=log(2013)33+log(2013)61=log(2013)(3...请用初二数学解答下面应该是初二的：33^x=33*61 两边除以33∴33^(x-1)=61①∵61^y=33*61两边同时除以61:∴61^(y-1)=33②①代入②：[33^(x-1)]^(y-1)=33即33^[(x-1)(y-1)]=33∴(x-1)(y-1)=1∴xy-x-y+1=1∴xy-x-y=0两边同时除以xy 1-1/y-1/x=0即1/x+1/y=1我们才学到积的乘方还有幂的次方，同底数幂相乘同底数幂相除呢？这里用到了没学开方呀没有学开方的那个解法，我给删掉了33^x=33*61 两边除以33∴33^(x-1)=61①∵61^y=33*61两边同时除以61:∴61^(y-1)=33②①代入②：[33^(x-1)]^(y-1)=33即33^[(x-1)(y-1)]=33∴(x-1)(y-1)=1∴xy-x-y+1=1∴xy-x-y=0两边同时除以xy 1-1/y-1/x=0即1/x+1/y=1Petty good！OL