求(sin10°-根号3cos10°)/sin50°_数学解答

求(sin10°-根号3cos10°)/sin50°

人气：213 ℃　时间：2020-05-11 12:19:24

解答

(sin10°-√3cos10°)/sin50°
=(2sin10°cos60°-2cos10°sin60°)/sin50°
=2sin(-50°)/sin50°
=-2