初二数学分式计算1/(x-3)-6/(x2-9)-(x-1)/(6+2x)_数学解答

初二数学分式计算
1/(x-3)-6/(x2-9)-(x-1)/(6+2x)

人气：410 ℃　时间：2020-01-29 07:19:20

解答

1/(x-3)-6/(x2-9)-(x-1)/(6+2x)
=1/(x-3)-6/[(x+3)(x-3)]-(x-1)/[2(x+3)]
=[2x+6-6*2-(x-1)*(x-3)]/[2(x+3)(x-3)]
=(3-x)/(6+2x)