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初二数学 分式 计算
1/(x-3)-6/(x2-9)-(x-1)/(6+2x)
人气:293 ℃ 时间:2020-01-29 07:19:20
解答
1/(x-3)-6/(x2-9)-(x-1)/(6+2x)
=1/(x-3)-6/[(x+3)(x-3)]-(x-1)/[2(x+3)]
=[2x+6-6*2-(x-1)*(x-3)]/[2(x+3)(x-3)]
=(3-x)/(6+2x)
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