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x=(e^t)sint y=(e^t)cost 求d^2y/dx^2
人气:404 ℃ 时间:2020-02-04 12:22:58
解答
dx/dt=(e^t)sint+(e^t)cost=(e^t)(sint+cost)
dy/dt=(e^t)cost-(e^t)sint=(e^t)(cost-sint)
dy/dx=(dy/dt)/(dx/dt)=(cost-sint)/(sint+cost)
d^2y/dx^2
=d(dy/dx)/dx
=[d(dy/dx)/dt]/[dx/dt]
={[-(sint+cost)^2-(cost-sint)^2]/(sint+cost)^2}/[(e^t)(sint+cost)]
=-2[e^(-t)]/(sint+cost)^3
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