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lim(x->1)lnx*ln(x 1)等于多少
是lim(x->1)ln(x)ln(x-1)
人气:155 ℃ 时间:2020-03-23 09:44:28
解答
lim(x->1)ln(x)ln(x-1)
=lim(x->1)ln(x-1)/[1/ln(x)]
=lim(x->1)ln(x-1)'/[1/ln(x)]'
=-lim(x->1)x*lnx*lnx/(x-1)
=-lim(x->1)[lnx*lnx]'/(x-1)'
=-lim(x->1)2*lnx/x=-2*ln1=0
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