计算:a(a+1) +1/(a+1)(a+2) +1/(a+2)(a+3) + +1/(a+2004)(a+2005)
人气:431 ℃ 时间:2019-12-09 21:41:00
解答
1/(a+1)(a+2)=1/(a+1)-1/(a+2)同理:1/(a+2)(a+3)=1/(a+2)-1/(a+3)所以:a(a+1) +1/(a+1)(a+2) +1/(a+2)(a+3) + +1/(a+2004)(a+2005)=a(a+1)+1/(a+1)-1/(a+2)+1/(a+2)-1/(a+3)+.+1/(a+2004)-1/(a+2005) ...抱歉,是1/a(a+1) +1/(a+1)(a+2) +1/(a+2)(a+3) + +1/(a+2004)(a+2005)那就对了,答案就是我写的最后一行了,看明白了吗?
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