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lim x->0 [(tanx-sinx)/(x-x*cos2x)]
人气:114 ℃ 时间:2020-05-13 22:12:26
解答
lim x->0 [(tanx-sinx)/(x-x*cos2x)]
=lim x->0 [sinx(1-cosx)/cosx]/(x(1-cos2x)
=lim x->0 [sinx*2(sin(x/2))^2]/[cosx*x*2(sinx)^2]
=lim x->0 [x*2(x/2)^2]/(x*2x^2)
=1/4
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