(x-3)^2-(x-1)(x-2)-7(x+1)简便运算 （12a^4b^5-4a^8b^3-6a^2b^3)除以2a^2b^3
人气：493 ℃ 时间：2020-04-08 13:02:08
解答
=x²-6x+9-(x²-3x+2)-7x+7
=-10x+14
（12a^4b^5-4a^8b^3-6a^2b^3)除以2a^2b^3
=12a^4b^5除以2a^2b^3-4a^8b^3除以2a^2b^3-6a^2b^3除以2a^2b^3
=6a²b²-2a^6-3
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