y=ln[arctan(1-x)],这dy=
人气:123 ℃ 时间:2020-03-28 17:21:35
解答
y'=1/arctan(1-x)*1/[1+(1-x)²]*(1-x)'
=-1/[(x²-2x+2)arctan(1-x)]
所以
dy=-1/[(x²-2x+2)arctan(1-x)]dx
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