(1)设(x,y)∵l是BC的垂直平分线,
∴|DB|=|DC|
∴|DB|+|DA|=|AC|=2
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∴D点的轨迹图形E是A,B为焦点的椭圆 其中2a=2
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∴a=
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∴D点的轨迹图形E:
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(2)设 P(x,y)x∈[-
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则PO2=x2+y2,
PF2=(x-1)2+y2
∴|PO|2+|PF|2=2x2-2x+2y2+1
点P(x,y)满足
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∴2y2=2-x2
∴|PO|2+|PF|2=x2-2x+3=(x-1)2+2
∵x∈[-
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(1)设(x,y)| 2 |
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