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计算:1/a-x - 1/a+x -2x/a²+x² + 4a²x/(a²)²-(x²)²
人气:381 ℃ 时间:2020-05-22 22:34:12
解答
1/(a-x)-1/(a+x)-2x/(a²+x²)+4a²x/[(a²)²-(x²)²]
=[a+x-(a-x)]/(a²-x²)-2x/(a²+x²)+4a²x/[(a²)²-(x²)²]
=2x/(a²-x²)-2x/(a²+x²)+4a²x/[(a²)²-(x²)²]
=2x[(a²+x²)-(a²-x²)]/[(a²)²-(x²)²]+4a²x/[(a²)²-(x²)²]
=4x³/[(a²)²-(x²)²]+4a²x/[(a²)²-(x²)²]
=4x(a²+x²)/[(a²)²-(x²)²]
=4x/(a²-x²)
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