∵(k+1)x^|k|+1-(k-2)x-3=0是一元一次方程.∴|k|=1或|k|=0(1)k=-1则(-1+1)x+1-(-1-2)x-3=03x-2=0x=2/3(2)k=1则(1+1)x+1-(1-2)x-3=02x+1+x-3=03x-2=0x=2/3(3)k=0则(0+1)x^0+1-(0-2)x-3=01+1+2x-3=02x-1=0x=1/2综上,x=...