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解方程 log2(x^2-3)=2log4(6x-10)-1
等于2
人气:423 ℃ 时间:2020-05-20 15:31:29
解答
log2(x^2-3)=2log4(6x-10)-1=》log2(x^2-3)=log4(6x-10)^2-1=>log2(x^2-3)=log2(6x-10)-1=》log2(x^2-3)=log2(6x-10)/2=>x^2-3=(6x-10)/2=>x^2-3x+2=0=>x1=1(因为x^2-3x=2
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