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解方程log2(x^2-3)=log2(6x-10)-1
人气:231 ℃ 时间:2020-05-22 04:27:49
解答
log2(x^2-3)=log2(6x-10)-1即log2(x^2-3)=log2(6x-10)/2x²-3=(6x-10)/2①x²-3>0②6x-10>0③由①得2x²-6=6x-102x²-6x+4=0x²-3x+2=0(x-1)(x-2)=0x=1或x=2又因为必须满足②③,所以代入检验发...
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