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已知cos2a=3/5,求sin^4*a+cos^4*a=?
人气:426 ℃ 时间:2020-03-24 11:59:40
解答
cos2a=3/5(sin2a)^2= (1-(cos2a)^2 = 16/25cos^2a - sin^2a = 3/5(cos^2a - sin^2a )^2 = 9/25(cos^2a - sin^2a )^2 = 9/25sin^4*a+cos^4*a-2(sinacosa)^2 = 9/25sin^4*a+cos^4*a-1/2(sin2a)^2 = 9/25sin^4*a+cos^4*...
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