∵(x²+y)dx+(x+y)dy=0 ==>x²dx+ydx+xdy+ydy=0==>d(x³/3)+d(xy)+d(y²/2)=0==>d(x³/3+xy+y²/2)=0∴原方程的通解是x³/3+xy+y²/2=C (C是积分常数).