解；
f(x)=sinx+sinxcosπ/3+cosxsinπ/3
=sinx+1/2sinx+√3/2cosx
=3/2sinx+√3/2cosx
=√3sin(x+π/6)
当x+π/6=-π/2+2kπ
即x=-2π/3+2kπ时
f(x)取得最小值为：-√3
∴f(x)取得最小值的x的集合为：{x/x=2kπ-2π/3,k∈z}因为y=sinx在x=-π/2+2kπ时取得最小值对应上面那道题必须是：x+π/6=-π/2+2kπ