(lg2/lg3+lg2/2lg3)*(lg3/2lg2+lg3/3lg2)
=[(2lg2+lg2)/2lg3][(3lg3+2lg3)/lg2)
=(3lg2/2lg3)(5lg3/6lg2)
=3/2x5/6
=5/43/2x5/6？帮帮忙吧，都忘光了，谢谢。3/2x5/6=(3x5)÷(2x6)=5/4