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已知集合M={sinx>cosx,0≤x≤π/2},N=﹛sinx<tanx﹜,则M∧N=
人气:142 ℃ 时间:2020-06-13 03:16:12
解答
M∩N={sinx>cosx且sinx<tanx,0≤x≤π/2}
sinx>cosx,0≤x≤π/2得π/4<x≤π/2;
sinx<tanx=sinx/cosx,cosx≠0,则x≠π/2;
所以
M∩N={π/4<x<π/2}.
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