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数学
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因式分解1.(a²+b²)²-4a²b² 2.x²-y²-x-y
人气:412 ℃ 时间:2020-01-27 08:26:23
解答
1.(a²+b²)²-4a²b²原式=(a²+b²)²-(2ab)²=(a²+b²+2ab)(a²+b²-2ab)=(a+b)²(a-b)²2.x²-y²-x-y原式=(x²-y²)-(x+y)=(x+...
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