sin^2a+2sinacosa+1=(sina+cosa)^2+sin^2a
=[(sina+cosa)^2+sin^2a]/1
=[(sina+cosa)^2+sin^2a]/(sin^2a+cos^2a)
=[(tana+1)^2+tan^2a]/(tan^2a+1)
=[(2+1)^2+2^2]/(2^2+1)
=13/5