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解方程组3x^2-y^2=8&x^2+xy+y^2=4
人气:464 ℃ 时间:2019-11-03 22:04:37
解答
x^2+xy+y^2=4=>2x^2+2xy+2y^2=8联立3x^2-y^2=8相减得=>x^2-2xy-3y^2=0=>(x-3y)(x+y)=0=>x=3y或x=-y讨论:1)x=3y=>3(3y)^2-y^2=8=>26y^2=8=>y=正负(根号(4/13))x=正负3*(根号(4/13))2)x=-y=>(-y)^2+(-y)*y+y^...
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