弧长C=6.9米,弦长L=6米,求弓高H?弧半径为R,弧所对的圆心角为A.Rn+1=(1+(L-2*Rn*SIN(C/(2*Rn)))/(L-C*COS(C/(2*Rn))))*RnR0=4R1=3.799R2=3.821R3=3.821R=3.821米A=2*ARC SIN((L/2)/R)=2*ARC SIN((6/2)/3.821)=103.466...