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(xy-1)^2+(x+y-2xy)(x+y-2) 因式分解,用换元法做,设t
人气:364 ℃ 时间:2020-06-15 14:30:13
解答
设xy=m,x+y=n
原式=(m-1)^2+(n-2m)(n-2)
=m^2-2m+1+n^2-(2+2m)n+4m
=(m-n)^2+2(m-n)
=(m-n)(m-n+2)
=(xy-x-y)(xy-x-y+2)t设x+y=t
原式=(xy-1)^2+(t-2xy)(t-2)
=(xy)^2-2xy+1+t^-2xyt-2t+4xy
=(xy-t)^2+2(xy-t)
=(xy-t)(xy-t+2)
=(xy-x-y)(xy-x-y+2)
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