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(cosx+sinx)平方+根号3倍cos2x-1在区间(O,π/2)的最大值和最小值
人气:208 ℃ 时间:2019-10-10 00:42:24
解答
y=(sinx+cosx)²+√3cos2x-1
=sin²x+cos²x+2sinxconx+√3cos2x-1
=1+sin2x+√3cos2x-1
=2sin(2x+π/3)
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